ESTIMATION OF HEMOGLOBIN F (HBF/Foetal Hemoglobin) BY ALKALI DENATURATION METHOD
Foetal hemoglobin
(HbF) constitutes 70 to 90 % of the total hemoglobin at birth, but is replaced
by the adult hemoglobin (HbA) during the first few months after birth.
Hbf consists of two alpha (a) and two gamma (7) chains in its globin molecule, and each chain is linked with a haem group. When HbF is converted to HbA, an amino acid in the gamma chain is replaced, and the resulting chain is called a beta (P) chain. Thus
Hbf consists of two alpha (a) and two gamma (7) chains in its globin molecule, and each chain is linked with a haem group. When HbF is converted to HbA, an amino acid in the gamma chain is replaced, and the resulting chain is called a beta (P) chain. Thus
Globin
chains in Hb A 2a and 2 B
Globin
chains in Hb F 2 a and, 27
In
beta-thalassaemia, there is a decrease in the synthesis of beta chains, and
therefore, an increase in HbF.
Principle of HBF
HbF is more
resistant to denaturation by alkali than HbA. This property is used to estimate
the amount of Hbf in a blood sample. A haemolysate is prepared. A measured
quantity of the haemolysate is exposed to the action of an alkaline reagent for
a defined period of time.
Denaturation process is interrupted by adding a solution
which simultaneously lowers the pH and precipitates the denatured hemoglobin.
After filtration, the unaltered hemoglobin (HbF) is determined by reading the
absorbance of the filtrate. This is expressed as a percentage of total initial
amount of hemoglobin present in the specimen of blood.
Specimen Blood anticoaguled with EDTA.
Reagents of HBF
1. Sodium or
potassium hydroxide (0.083 N): Dilute before use, I N NaOH or KOH 1:12. (8.3 ml
of IN solution to 100 ml with distilled water).
2.
Precipitating agent: Add 2 ml of concentrated hydrochloric acid to 500ml of
half saturated ammonium sulphate solution. Prepare saturated ammonium sulphate
solution by adding about 500g of the salt to 500ml water. Allow it to stand for
1-2 hours. Dilute the supernatant 1:2 to obtain a halfsaturated solution.
3. Sodium
chloride 0.85 % solution.
4.
Chloroform
Technique of HBF
Step 1 Preparation of haemolysate
Centrifuge the specimen of blood.
Wash the
cells three times with the sodium chloride solution.
For lysing
the cells, shake each volume of packed cells (0.4 ml) vigorously with equal
volume of distilled water (0.4 ml) and half volume of chloroform (0.2 ml) for
two minutes.
Centrifuge
at 3000 rpm for 20 minutes.
Remove the
upper layer of haemoglobin. Filter to clear if necessary.
Determine
the haemoglobin concentration of the haemolysate by one of the standard methods
in use. e.g. cyanmethaemoglobin method.
Adjust the
haemoglobin concentration of the haemolysate to approximately 10g %. For
example, if haemoglobin content of the haemolysate is 13g%. add 0.3 ml of
distilled water to 1.0 ml of the haemolysate to obtain the concentration equal
to 10 g %.
Step II Alkali denaturation
Place 3.0 ml of 0.083 N hydroxide solution in
a test tube.
Add 0.2 ml
of the haemolysate quickly from a pipette and gently shake the tube for 10
seconds. Start a stop watch at the time of adding the haemolysate.
At the end
of exactly 1 minute, add 6.8 ml precipitating agent.
Mix by
inverting several times and filter through two layers of Whatman No. 1 filter
paper.
With normal adult haemoglobin, the filtrate is colourless whereas in the presence haemoglobin F. the filtrate may be light brown to deep red in colour.
With normal adult haemoglobin, the filtrate is colourless whereas in the presence haemoglobin F. the filtrate may be light brown to deep red in colour.
Prepare a
standard haemoglobin solution by diluting 0.2 ml of the haemolysate prepared in
Step I to 200 ml with 0.04% ammonia solution. This corresponds to 5% alkali
resistant haemoglobin.
Read the
absorbance of the standard and test against a water blank using a blue filter (415
nm).
Calculations of HBF
(i) The
amount of foetal haemoglobin (HbF) is expressed as a percentage of total
haemoglobin (HbF + HbA).
(ii) During
alkali denaturation, 0.2 ml of the haemolysate is diluted to 10 ml (1:50
dilution).
(iii) If all
the haemoglobin is in the form of alkali resistant haemoglobin (HbF), the
absorbance of 1:50 dilution should be equivalent to 100 % HbF.
(iv)
Therefore, 0.2 ml of the haemolysate diluted to 200 ml (1:1000 dilution) is
equivalent to 5 % HDF Alkali
resistant hemoglobin (%) = Reading of test/Reading of standard
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